Question

Три группы учеников убирают площадку. Первая группа убрала 7/12 площадки, вторая — 2/3 оставшейся части, а третья — остальную часть. Какую часть всей площадки убрала третья группа? ​

Answer 1

площадь всей площадки 1

1-7/12=5/12, осталось вторая убрала (2/3)*(5/12)=5/18

третья убрала 5/12-5/18=(15-10)/36=5/36

Answer 2

Question Analysis

The question asks about the portion of the entire playground that the third group of students cleaned. The first group cleaned 7/12 of the playground, and the second group cleaned 2/3 of the remaining portion. We need to determine the portion cleaned by the third group.

Answer

To find the portion of the playground cleaned by the third group, we need to calculate the remaining fraction after the first and second groups have cleaned their portions.

Let's break down the problem step by step:

1. The first group cleaned 7/12 of the playground. 2. The second group cleaned 2/3 of the remaining portion after the first group cleaned. 3. The third group cleaned the remaining portion.

To calculate the remaining portion, we need to subtract the portions cleaned by the first and second groups from the total playground.

Let's calculate the remaining portion:

1. The first group cleaned 7/12 of the playground. 2. The remaining portion after the first group cleaned is 5/12 (12/12 - 7/12). 3. The second group cleaned 2/3 of the remaining portion. 4. The portion remaining after the second group cleaned is 1/3 of the remaining portion (5/12 * 1/3). 5. Therefore, the third group cleaned the remaining portion, which is 1/3 of the playground.

So, the third group cleaned 1/3 of the entire playground.

Answer: 1/3

Please let me know if there is anything else I can help you with.