Question

1) (×-1)(×-7)=0 2)(×+1)(×-1)(×-5)=0 yordam beringlar tezroq​

Answer 1

Ответ:

1) х₁ = 1,   х₂ = 7

2) х₁ = -1, х₂ = 1, х₃ = 5

Пошаговое объяснение:

1) (х - 1)(х - 7) = 0

  х₁ - 1 = 0     х₂ - 7 = 0

  х₁ = 0 + 1    х₂ = 0 + 7

  х₁ = 1          х₂ = 7

2) (х + 1)(х - 1)(х - 5) = 0

   х₁ + 1 = 0            х₂ - 1 = 0             х₃ - 5 = 0

   х₁ = 0 - 1 = -1      х₂ = 0 + 1 = 1       х₃ = 0 + 5 = 5

Правило:

Когда уравнение состоит из множителей и равно нулю, один из множителей должен быть равен нулю.

Answer 2

1. (×-1)(×-7)=0 To find the solutions, we need to set each factor equal to zero and solve for ×:

Setting × - 1 = 0: × = 1

Setting × - 7 = 0: × = 7

Therefore, the solutions to the equation (× - 1)(× - 7) = 0 are × = 1 and × = 7.

2. (× + 1)(× - 1)(× - 5) = 0 To find the solutions, we set each factor equal to zero and solve for ×:

Setting × + 1 = 0: × = -1

Setting × - 1 = 0: × = 1

Setting × - 5 = 0: × = 5

Therefore, the solutions to the equation (× + 1)(× - 1)(× - 5) = 0 are × = -1, × = 1, and × = 5.