Question

A) (1 + 5a) + (a² − 3a); c) (y² - 5y + 1) + (5y - 2y²); 2 b) (3x² − 2x) − (−x² − 3x + 5); d) (b²+b-7) - (b²-b-8).​

Answer 1

Ответ: а) а² + 2а + 1; b) 4х² + х - 5; c) -у² + 1; d) 2b + 1.​

Пошаговое объяснение:

Скорее всего нужно найти сумму или разность многочленов:

а) (1 + 5a) + (a² - 3a) = 1 + 5а + а² - 3а = а² + 2а + 1;

b) (3x² - 2x) - (-x² - 3x + 5) = 3х² - 2х + х² + 3х - 5 = 4х² + х - 5;

c) (y² - 5y + 1) + (5y - 2y²) = у² - 5у + 1 + 5у - 2у² = -у² + 1;

d) (b² + b - 7) - (b² - b - 8) = b² + b - 7 - b² + b + 8 = 2b + 1.​

Answer 2

Let's simplify each expression:

A) (1 + 5a) + (a² - 3a)

To simplify, we can combine like terms. The terms with "a" can be added together:

= 1 + 5a + a² - 3a

Now, combining the "a" terms:

= 1 + a² + 2a

So, the simplified expression is 1 + a² + 2a.

B) (3x² - 2x) - (-x² - 3x + 5)

To simplify, we need to distribute the negative sign across the terms inside the parentheses:

= 3x² - 2x + x² + 3x - 5

Now, we can combine like terms:

= (3x² + x²) + (-2x + 3x) - 5

= 4x² + x - 5

So, the simplified expression is 4x² + x - 5.

C) (y² - 5y + 1) + (5y - 2y²)

To simplify, we need to combine like terms. The terms with "y" can be added together:

= y² - 2y² - 5y + 5y + 1

Now, combining the "y" terms:

= -y² + 1

So, the simplified expression is -y² + 1.

D) (b² + b - 7) - (b² - b - 8)

To simplify, we need to distribute the negative sign across the terms inside the parentheses:

= b² + b - 7 - b² + b + 8

Now, we can combine like terms:

= (b² - b²) + (b + b) + (-7 + 8)

= 0 + 2b + 1

So, the simplified expression is 2b + 1.