Question

(d-295)×13=260 25×(540-s)=25000 t:(6000-5996)=600

Answer 1

1) (d-295)*13=260
d*13-295*13=260
13d=260+295*13
d=260:13+295*13:13
d=20+295
d=315
2)25*(540-s)=25000
540-s=25000:25
540-s=1000
s=540-1000
s=-460
3)t:(6000-5996)=600
t:4=600
t=600*4
t=2400

Answer 2

To solve these equations, we can use the basic algebraic operations of addition, subtraction, multiplication, and division.

1. (d-295)×13=260

First, we can simplify the left side of the equation by distributing the 13 to d and -295:

13d - 13×295 = 260

Next, we can combine the like terms on the left side of the equation:

13d - 3835 = 260

Then, we can isolate the variable d by adding 3835 to both sides of the equation:

13d = 4095

Finally, we can solve for d by dividing both sides of the equation by 13:

d = 315

Therefore, the solution to the equation (d-295)×13=260 is d = 315.

2. 25×(540-s)=25000

First, we can simplify the left side of the equation by distributing the 25 to 540 and -s:

25×540 - 25s = 25000

Next, we can simplify the left side of the equation by multiplying:

13500 - 25s = 25000

Then, we can isolate the variable s by subtracting 13500 from both sides of the equation:

-25s = 11500

Finally, we can solve for s by dividing both sides of the equation by -25 and remembering to flip the inequality sign since we're dividing by a negative number:

s = -460

Therefore, the solution to the equation 25×(540-s)=25000 is s = -460.

3. t:(6000-5996)=600

First, we can simplify the left side of the equation by subtracting 6000 and 5996:

t:4=600

Next, we can isolate the variable t by multiplying both sides of the equation by 4:

t = 2400

Therefore, the solution to the equation t:(6000-5996)=600 is t = 2400.