Question

1) 52 -(19+х)=17 ; 77/(у+10)=7 2)Из города выехал мотоциклист со скоростью 40 км/ч. Через 2 ч в том направлении из города выехал автомобиль со скоростью 80 км /ч . Через сколько времени после выезда автомобиль догонит мотоциклиста ? На каком расстоянии от города это произойдет ?

Answer 1

1)   52 -(19+х)=17
    19+х=35
      х=35-19
      х=16
Ответ16

77/(у+10)=7
у+10=11
у=11-10
y=1
ответ1
2) Ответ: через 4 часа.           

Answer 2

52-19-x=17;
x=52-19-17;
x=16;
77/(y+10)=7;
y=77/7-10;
y=1;
T=4 часа
S=160км
V1*T0=V2(T1-T0)
t1=v1*t0/v2+t0=4
S=V2*(t1-t0)=160км

Answer 3

To solve the first set of equations:

52 - (19 + x) = 17

We can simplify by combining like terms:

52 - 19 - x = 17

33 - x = 17

Next, we can isolate the variable x by adding x to both sides:

33 - x + x = 17 + x

33 = 17 + x

Finally, we can isolate x by subtracting 17 from both sides:

33 - 17 = x

x = 16

Now let's solve the second equation:

77 / (y + 10) = 7

We can simplify by multiplying both sides by (y + 10):

77 = 7(y + 10)

Distribute the 7 on the right-hand side:

77 = 7y + 70

Subtract 70 from both sides:

7 = 7y

Divide both sides by 7:

y = 1

So the solutions to the system of equations are x = 16 and y = 1.

To solve the second problem, we need to find the time it takes for the car to catch up to the motorcycle, as well as the distance from the city where this occurs.

We can start by using the formula:

distance = rate x time

Let's call the time it takes for the car to catch up to the motorcycle "t".

The distance the motorcycle travels in this time is:

distance = rate x time = 40 km/h x t = 40t km

The distance the car travels in this time is:

distance = rate x time = 80 km/h x (t - 2) = 80t - 160 km

When the car catches up to the motorcycle, they will have traveled the same distance. So we can set these two distances equal to each other and solve for t:

40t = 80t - 160

Subtract 40t from both sides:

-40t = -160

Divide both sides by -40:

t = 4

So it takes 4 hours for the car to catch up to the motorcycle.

To find the distance from the city where this occurs, we can plug t = 4 into either of the distance equations we derived earlier. Let's use the equation for the car's distance:

distance = 80t - 160 = 80(4) - 160 = 160 km

So the car catches up to the motorcycle 160 km from the city.