Question

1)3(x+6)=x+2(x+9) 2)2(8x-7)=18-4(5-4x).

Answer 1

1)3(x+6)=x+2(x+9)
3х+18=х+2х+18
3х+18=3х+18
3х-3х=18-18
0=0

2)2(8x-7)=18-4(5-4x).
16х-14=18-20+16х
16х-14=-2+16х
16х-16х=-2+14
0=12

Answer 2

1. Starting with the left-hand side of the equation:

3(x+6) = 3x + 18

And now the right-hand side of the equation:

x+2(x+9) = x+2x+18 = 3x+18

So we have:

3x+18 = 3x+18

This equation is true for any value of x, which means that there are infinitely many solutions.

2. Starting with the left-hand side of the equation:

2(8x-7) = 16x - 14

And now the right-hand side of the equation:

18 - 4(5-4x) = 18 - 20 + 16x = -2 + 16x

So we have:

16x - 14 = -2 + 16x

Subtracting 16x from both sides gives:

-14 = -2

This equation is not true, so there is no solution that satisfies it. Therefore, the original equation has no solution.