Question

1) 0,2 x+3 = 0,7x-2             2) x-3 6стых =7целых 3десятых

Answer 1

1) 0,2 x+3 = 0,7x-2

     0,2х-0,7х=-2-3

      -0,5х=-5

         х=-5:(-0,5)

         х=10

 

2) $x-\frac{3}{6}=7\frac{3}{10}$

     $x=7\frac{3}{10}+\frac{3}{6}$

$x=7\frac{18}{60}+\frac{30}{60}$

$x=7\frac{48}{60}$

$x=7\frac{4}{5}$

Answer 2

1. To solve the equation 0,2x + 3 = 0,7x - 2, we want to isolate the variable x on one side of the equation. We can start by subtracting 0,2x from both sides:

0,2x + 3 - 0,2x = 0,7x - 2 - 0,2x

Simplifying the left side:

3 = 0,5x - 2

Next, we add 2 to both sides:

3 + 2 = 0,5x - 2 + 2

Simplifying:

5 = 0,5x

Finally, we divide both sides by 0,5 to solve for x:

5 ÷ 0,5 = x

x = 10

Therefore, the solution to the equation 0,2x + 3 = 0,7x - 2 is x = 10.

2. To solve the equation x - 3 6/10 = 7 3/10, we want to isolate the variable x on one side of the equation. We can start by adding 3 6/10 to both sides:

x - 3 6/10 + 3 6/10 = 7 3/10 + 3 6/10

Simplifying the left side:

x = 10

Simplifying the right side:

7 3/10 + 3 6/10 = 10

Therefore, the solution to the equation x - 3 6/10 = 7 3/10 is x = 10.