Question

52-(3y+4+y+4y)×38=50 решить

Answer 1

52-(3y+6+y+3y):38=50
52-(3y+6+4y):38=50
52-(7y+6):38=50
-(7y+6):38=50-52
-(7y+6):38=-2
-7y-6=(-2)*38
-7y-6=-76
-7y=-76+6
-7y=-70
7y=70
y=70/7=10
вконце можешь написать
у=70/7
у=10
можешь как угодно написать

Answer 2

To solve this equation, we need to simplify the expression on the left side first using the order of operations (PEMDAS):

52 - (3y + 4 + y + 4y) × 38 = 50

52 - (5y + 4) × 38 = 50 (combine like terms inside the parentheses)

52 - (190y + 152) = 50 (distribute the 38)

-190y - 100 = -2 (combine like terms on both sides)

-190y = -98 (add 100 to both sides)

y = 98/190 (divide both sides by -190)

y ≈ -0.516 (simplify)

Therefore, the solution to the equation is y ≈ -0.516.