Question

4+(3y) =7, (y)-2=1,(5y) -4=6

Answer 1

Відповідь:y=1

y=3

y=2

Покрокове пояснення:

1) 3y=7-4

3y=3

y=1

2) y-2=1

y=1+2

y=3

3) 5y-4=6

5y=6+4

5y=10

y=10/5

y=2

Answer 2

To solve the given equations, let's go through each one step by step:

1. 4 + 3y = 7

To isolate the variable y, we need to move the constant term 4 to the other side of the equation by subtracting it from both sides:

4 + 3y - 4 = 7 - 4 3y = 3

Now, divide both sides of the equation by 3 to solve for y:

(3y)/3 = 3/3 y = 1

So, the solution for the first equation is y = 1.

2. y - 2 = 1

To isolate the variable y, we can move the constant term -2 to the other side by adding 2 to both sides:

y - 2 + 2 = 1 + 2 y = 3

Therefore, the solution for the second equation is y = 3.

3. 5y - 4 = 6

First, let's move the constant term -4 to the other side by adding 4 to both sides:

5y - 4 + 4 = 6 + 4 5y = 10

Now, divide both sides of the equation by 5:

(5y)/5 = 10/5 y = 2

Hence, the solution for the third equation is y = 2.

To summarize, the solutions for the given equations are:

1. y = 1
2. y = 3
3. y = 2