Question

1) ||х-3|=0, 2) |5-х||=0, 3) ||х+3|=0, 4) |7-х||=0

Answer 1

1) |х-3|=0x-3=0
x=3
2) |5-х|=05-x=0
x=5
3) |х+3|=0 x+3=0 x=-3
 4) |7-х|=0 7-x=0
x=7

Answer 2

1)|x-3|=0
x-3=0
x=3+0
х=3
|3-3|=0
Ответ:х=3
2)|5-х|=0
5-х=0
х=5-0
х=5
|5-5|=0
Ответ:х=5
3)|х+3|=0
х+3=0
х=0-3
х=-3
|-3+3|=0
Ответ:х=-3
4)|7-х|=0
7-х=0
х=7-0
х=7

|7-7|=0
Ответ:х=7

Answer 3

Let's solve each of these equations step by step:

1. ||x-3| = 0:

Since the absolute value of any number is always non-negative, the only way for the absolute value to equal zero is when the expression inside it equals zero. Therefore, we have:

|x - 3| = 0

This implies that x - 3 = 0, so we solve for x:

x - 3 = 0 x = 3

Therefore, the solution to this equation is x = 3.

2. |5 - x| = 0:

Similar to the previous equation, the absolute value can only equal zero when the expression inside it equals zero:

|5 - x| = 0

This implies that 5 - x = 0, so we solve for x:

5 - x = 0 x = 5

The solution to this equation is x = 5.

3. ||x + 3| = 0:

Just like in the first equation, the outer absolute value sign ensures that the expression inside it must equal zero. So we have:

|x + 3| = 0

This implies that x + 3 = 0, so we solve for x:

x + 3 = 0 x = -3

The solution to this equation is x = -3.

4. |7 - x| = 0:

Similar to the previous equations, the absolute value can only equal zero when the expression inside it equals zero:

|7 - x| = 0

This implies that 7 - x = 0, so we solve for x:

7 - x = 0 x = 7

The solution to this equation is x = 7.

To summarize:

1. x = 3
2. x = 5
3. x = -3
4. x = 7