Question

Найдите диагональ ромба,если вторая диагональ и сторона ромба соответственно равны 16 и 10(Теорема Пифагора)

Answer 1

Теорема Пифагора: c²=a²+b² (Где a и b катеты,а с-гипотенуза)
Для начала найдём 1/2 второй диагонали : 16:2=8
Дальше по теореме Пифагора находим 1\2 нужной нам диагонали:
10²-8² = √36=6
Сама диагональ будет равна: 6*2=12

Answer 2

Finding the Diagonal of a Rhombus

To find the diagonal of a rhombus, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In the case of a rhombus, the diagonals are perpendicular bisectors of each other, meaning they intersect at a right angle. Therefore, we can consider each diagonal as the hypotenuse of a right triangle formed by half of the rhombus and one of its sides.

Let's denote the first diagonal as d1 and the second diagonal as d2. We are given that d2 is equal to 16 units and one side of the rhombus is equal to 10 units.

Using the Pythagorean theorem, we can set up the following equation:

d1^2 = (10/2)^2 + 16^2

Simplifying the equation:

d1^2 = 5^2 + 16^2

d1^2 = 25 + 256

d1^2 = 281

Taking the square root of both sides:

d1 = √281

Therefore, the diagonal of the rhombus is approximately equal to √281 units.