Question

Из вершины угла KOL равного 140 градусов проведены два луча: OB биссектриса угла,и OC делящий его в отношении 3:5,считая от стороны OL. Найдите все образовавшиеся углы. РЕШИТЕ ПОЖАЛУЙСТА!!!!

Answer 1

Совсем просто. уг КОЛ=140 ОВ-биссек.,следов. КОВ=ВОЛ=70гр.
Уг. КОЛ=140 и состоит из 3+5=8 частей.  140:8=17,5,  17,5*3=52,5, 
17,5*5=87,5

Answer 2

Finding the Angles

To find all the angles formed by the given scenario, we can use the information provided about the bisector and the division of the angle.

Solution:

1. Angle KOB: - Since OB is the bisector of angle KOL, angle KOB is half of angle KOL. - Angle KOB = 140 / 2 = 70 degrees.

2. Angle BOC: - Since OC divides angle KOL in the ratio 3:5, we can calculate the measure of angle BOC using the ratio. - Angle BOC = (3 / (3 + 5)) * 140 = (3/8) * 140 = 52.5 degrees.

3. Angle COB: - Angle COB is the complement of angle BOC. - Angle COB = 180 - 52.5 = 127.5 degrees.

4. Angle KOC: - Angle KOC is the sum of angles KOB and BOC. - Angle KOC = 70 + 52.5 = 122.5 degrees.

5. Angle KCO: - Angle KCO is the difference between angles KOL and KOC. - Angle KCO = 140 - 122.5 = 17.5 degrees.

6. Angle KOB, BOC, COB, KOC, KCO: - Angle KOB = 70 degrees - Angle BOC = 52.5 degrees - Angle COB = 127.5 degrees - Angle KOC = 122.5 degrees - Angle KCO = 17.5 degrees

These are the angles formed by the given scenario.