Question

Тупой угол ромба равен 150 градусов а его сторона равна 6 см.найдите площадь ромба

Answer 1

Из условия: $\angle ABC=\angle ADC=150а$, тогда $\angle BAD=\angle BCD=180а-150а=30а$

Площадь ромба через сторону и угол: $S=a^2\sin\alpha$

$S=AB^2\sin30а=6^2\cdot\frac{1}{2}=18$ см².

Ответ: 18 см².

Answer 2

Finding the Area of a Rhombus

To find the area of a rhombus, we need to know the length of one of its sides and the measure of one of its angles. In this case, we know that the measure of one of the angles of the rhombus is 150 degrees and that one of its sides is 6 cm long.

To find the area of the rhombus, we can use the formula:

Area = (side length)² * sin(angle)

Let's plug in the values we have:

Area = (6 cm)² * sin(150 degrees)

Now, let's calculate the area using the given values.

The sine of 150 degrees is 0.5.

Area = (6 cm)² * 0.5

Simplifying the equation:

Area = 36 cm² * 0.5

Area = 18 cm²

Therefore, the area of the given rhombus is 18 square centimeters.