Question

О- точка пересечения медиан равнобедренного треугольника АВС , АВ=ВС . ОК- часть медианы АК , ОК=4 см , найдите расстояние от середины боковой стороны до основания треугольника помогите решить​

Answer 1

Ответ:

4см

Объяснение:

Answer 2

Finding the Intersection Point of Medians in an Isosceles Triangle

To find the distance from the midpoint of the base to the intersection point of the medians in an isosceles triangle, we can use the following steps:

1. Identify the given information: - Triangle ABC is an isosceles triangle, with AB = BC. - OK is a part of the median AK, and OK = 4 cm.

2. Determine the properties of an isosceles triangle: - In an isosceles triangle, the medians are concurrent at a point called the centroid. - The centroid divides each median into two segments, with the segment closer to the vertex being twice as long as the segment closer to the base.

3. Use the properties of the centroid: - Let M be the midpoint of BC, and let X be the intersection point of the medians. - Since OK is a part of the median AK, we can say that AK = 2 * OK = 2 * 4 cm = 8 cm. - According to the properties of the centroid, MX = (2/3) * AM.

4. Find the length of AM: - Since AB = BC in an isosceles triangle, we can say that AM = (1/2) * BC. - Since AB = BC, we can substitute BC with AB in the equation, giving us AM = (1/2) * AB.

5. Calculate the distance from the midpoint of the base to the intersection point: - Using the information from steps 3 and 4, we can say that MX = (2/3) * (1/2) * AB = (1/3) * AB.

Therefore, the distance from the midpoint of the base to the intersection point of the medians is (1/3) * AB.

Note: The length of AB is not provided in the question, so we cannot determine the exact distance without that information.