Question

Одна із сторін трикутника вдвічі менша за другу та на 2 см більша третьої. Периметр трикутника 22 см. Знайдіть сторони цього трикутника. Розв'язок відправити на перевірку. відповіді: 6 12 8 4​

Answer 1

Решение на фото.......

Answer 2

Problem Analysis

We are given that one side of a triangle is half the length of the second side, and that the third side is 2 cm longer than the second side. The perimeter of the triangle is 22 cm. We need to find the lengths of the sides of this triangle.

Solution

Let's assume the length of the second side is x cm. According to the problem, the first side is half the length of the second side, so its length is x/2 cm. The third side is 2 cm longer than the second side, so its length is x + 2 cm.

The perimeter of a triangle is the sum of the lengths of its sides. In this case, the perimeter is given as 22 cm. So we can write the equation:

x/2 + x + (x + 2) = 22

To solve this equation, we can simplify it:

x/2 + x + x + 2 = 22

Combining like terms:

5x/2 + 2 = 22

Subtracting 2 from both sides:

5x/2 = 20

Multiplying both sides by 2/5 to isolate x:

x = 8

Now that we have the value of x, we can find the lengths of the sides of the triangle.

The first side is x/2 = 8/2 = 4 cm.

The second side is x = 8 cm.

The third side is x + 2 = 8 + 2 = 10 cm.

Therefore, the lengths of the sides of the triangle are 4 cm, 8 cm, and 10 cm.

Verification

Let's verify our solution by calculating the perimeter of the triangle using the lengths we found.

Perimeter = 4 cm + 8 cm + 10 cm = 22 cm.

The perimeter matches the given value of 22 cm, so our solution is correct.

Answer

The lengths of the sides of the triangle are 4 cm, 8 cm, and 10 cm.