Question

16.11. В равнобедренном треугольнике один угол на 90° меньше другого угла. Найдите больший угол.ПОМОГИТЕ ПЛИЗ СРОЧНО​

Answer 1

Ответ:

120°

Объяснение:

Сумма углов по теореме :

х+х+х+90°=180°

3х=90 °

Х=30°

Большой угол : 30° + 90° =120°

Ответ :120°

Х взят угол при основании, потому, что угол треугольника, больший на 90 градусов - тупой угол

Answer 2

Let's denote the measure of the larger angle as x. Since we know that one angle is 90° smaller than the other, we can express the measure of the other angle as (x + 90°).

In an isosceles triangle, the two base angles are equal. This means that the sum of these two angles is equal to the measure of the third angle:

(x + 90°) + (x + 90°) + x = 180°.

Simplifying the equation, we get:

3x + 180° = 180°.

Subtracting 180° from both sides, we have:

3x = 0°.

Dividing both sides by 3, we find:

x = 0°.

Since we know that x represents the measure of the larger angle, it means that the larger angle is 0°.

Therefore, the smaller angle is (0° + 90°) = 90°.

To summarize, the larger angle in the isosceles triangle is 0° and the smaller angle is 90°.