Question

Стороны параллелограмма 6 и 15см а площадь 45 см в квадрате Найти меньший угол параллелограмма

Answer 1

S=a*b*Sinγ

45=6*15*Sinγ

45=90*Sinγ

Sinγ=1/2 ⇒ угол = 30 гр.

угол β = (180-30-30)/2=60 гр.

 

меньший угол параллелограмма равен 30 градусов

Answer 2

отрый угол = 180-150 =30, S =6*8*sin30=24

Answer 3

Finding the Smaller Angle of a Parallelogram

To find the smaller angle of a parallelogram with sides of 6 cm and 15 cm and an area of 45 cm², we can use the formula for the area of a parallelogram and the properties of parallelograms to calculate the angle.

Calculating the Smaller Angle

The formula for the area of a parallelogram is given by the product of the base and the height: Area = base × height. In this case, the area is given as 45 cm², and one of the sides can be considered as the base. Let's denote the smaller angle of the parallelogram as θ.

Using the formula for the area of a parallelogram, we can express the height in terms of the area and the base: height = Area / base.

Now, we can use the sine function to find the smaller angle θ: sin(θ) = height / hypotenuse.

Given that the sides of the parallelogram are 6 cm and 15 cm, we can consider the side of length 6 cm as the base and the height as calculated above.

Let's calculate the value of θ using the given values.

Calculation

Using the formula for the area of a parallelogram, we can express the height in terms of the area and the base: height = Area / base. Substituting the given values: height = 45 / 6 = 7.5 cm.

Now, we can use the sine function to find the smaller angle θ: sin(θ) = height / hypotenuse. Substituting the values: sin(θ) = 7.5 / 15 = 0.5.

To find the angle θ, we can use the inverse sine function: θ = sin^(-1)(0.5).

Result

Calculating the value: θ ≈ 30 degrees.

Therefore, the smaller angle of the parallelogram is approximately 30 degrees.