Question

X^2+6-42=0_______________

Answer 1

Х^2=42-6
Х^2=36
Х=6
Ответ:6

Answer 2

To solve the quadratic equation $x^2 + 6x - 42 = 0$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a = 1$, $b = 6$, and $c = -42$. Plug these values into the formula:

$x = \frac{-6 \pm \sqrt{6^2 - 4(1)(-42)}}{2(1)}$

Now, calculate the values inside the square root:

$x = \frac{-6 \pm \sqrt{36 + 168}}{2}$ $x = \frac{-6 \pm \sqrt{204}}{2}$

Now, simplify the square root:

$x = \frac{-6 \pm \sqrt{4 \cdot 51}}{2}$ $x = \frac{-6 \pm 2\sqrt{51}}{2}$

Next, you can simplify further by dividing both the numerator and denominator by 2:

$x = \frac{-3 \pm \sqrt{51}}{1}$

So, the solutions to the equation $x^2 + 6x - 42 = 0$ are:

$x_1 = -3 + \sqrt{51}$ $x_2 = -3 - \sqrt{51}$

These are the two values of $x$ that satisfy the equation.