Question

Найти Ac,если Ab=6 и bc=3 a угол A=30

Answer 1

BC/SIN30 = AB/SIN X   3/1/2=6/SINX  ОТСЮДА Х = 90 ГРАДУСОВ
180-90-30=60.  АС/SIN60=BC/SIN30=AB/SIN90  ОТСЮДА АС=6*SIN60= 3*КОРЕНЬ(3)

Answer 2

To find the value of angle C (Ĉ) and side AC in the given triangle ABC, we can use the Law of Cosines, which relates the sides and angles of a triangle:

Law of Cosines: c^2 = a^2 + b^2 - 2ab * cos(Ĉ)

where c is the side opposite angle Ĉ, a and b are the other two sides, and Ĉ is the angle opposite side c.

Given: AB = 6 (a) BC = 3 (b) ∠A = 30°

We need to find AC (c) and ∠C (Ĉ).

1. First, let's find the length of side AC (c) using the Law of Cosines: c^2 = a^2 + b^2 - 2ab * cos(Ĉ)

Substitute the given values: AC^2 = 6^2 + 3^2 - 2 * 6 * 3 * cos(Ĉ)

2. Now, let's find the value of cos(Ĉ). We know that ∠A = 30°, so we can find ∠C (Ĉ) using the fact that the sum of angles in a triangle is 180°: ∠C = 180° - ∠A - ∠B ∠C = 180° - 30° - ∠B ∠C = 150° - ∠B

3. We need to find ∠B to calculate ∠C: ∠B = 180° - ∠A - ∠C ∠B = 180° - 30° - 150° ∠B = 0°

Note: This result indicates that the given angle values do not form a valid triangle. A triangle cannot have an angle with a measure of 0°.

If you have any other values for the angles or sides of the triangle, please provide them, and I'll be happy to help you further.