Question

Знайдіть кути рівнобедриного трикутника,якщо один з них на 40см більший від іншого розгляньте два випадки​

Answer 1

1 випадок:

(Коли вершина на 40° більша)

∠1=∠2=х

∠3=х+40

∠1+∠2+∠3=180°

х+х+х+40=180°

3х=140°

х=46,(6)≈47° - ∠1 та ∠2

х+40=86,(6)≈87° - ∠3

2 випадок:

(Коли кути при основі на 40° більші)

∠3=х

∠1=∠2=х+40°

∠1+∠2+∠3=180°

х+(х+40)+(х+40)=180°

3х=100°

х=33,(3)≈33° - ∠3

х+40=73,(3)≈73° - ∠1 та ∠2

Познач мою відповідь як найкращу, будь ласка))

Answer 2

Finding the Angles of an Isosceles Triangle

To find the angles of an isosceles triangle, we need to consider two cases: when one angle is 40 cm larger than the other, and when one angle is 40 cm smaller than the other.

Case 1: One angle is 40 cm larger than the other

Let's assume that one angle of the isosceles triangle is x cm. According to the given information, the other angle is 40 cm larger than x. Therefore, the second angle can be represented as (x + 40) cm.

In an isosceles triangle, the two equal angles are opposite the two equal sides. Since the triangle is isosceles, the two equal angles will be x cm and (x + 40) cm.

Case 2: One angle is 40 cm smaller than the other

Similarly, let's assume that one angle of the isosceles triangle is x cm. According to the given information, the other angle is 40 cm smaller than x. Therefore, the second angle can be represented as (x - 40) cm.

In this case, the two equal angles of the isosceles triangle will be x cm and (x - 40) cm.

To summarize:

Case 1: One angle is 40 cm larger than the other - Angle 1: x cm - Angle 2: (x + 40) cm

Case 2: One angle is 40 cm smaller than the other - Angle 1: x cm - Angle 2: (x - 40) cm

Please note that the exact values of the angles cannot be determined without additional information. The above information provides a general representation of the angles based on the given conditions.

I hope this helps! Let me know if you have any further questions.