Question

Выведите формулу W(N)=17,72%W(C)=75,95%W(H)=6,33%

Answer 1

NxCyHz - ? Требуется найти моль элемента в 1 моль вещества.

17,72% = 17,72 г N в 100 г в-ва, 75.95% = 17.95 г С, 6,33% - 6,33 г Н

n = m/M

n(N) : n(C) : n(H) = 17.72/14 : 75.95/12 : 6.33/1 = 1.27 : 6.33 : 6.33, после приведения к единице: 1 : 5 : 5

Эмпирическая формула NC5H5

Answer 2

The formula you provided seems to represent the relative atomic masses of the elements carbon (C), hydrogen (H), and nitrogen (N) in a particular compound. The percentages you mentioned indicate the weight percentage of each element in the compound.

To calculate the molar mass of the compound (W) based on these percentages, you can use the following formula:

W = (W(N) * M(N) + W(C) * M(C) + W(H) * M(H)) / 100

where:

• W(N), W(C), and W(H) are the weight percentages of nitrogen, carbon, and hydrogen, respectively.
• M(N), M(C), and M(H) are the molar masses of nitrogen, carbon, and hydrogen, respectively.

Using the atomic masses from the periodic table:

• M(N) = 14.01 g/mol (nitrogen)
• M(C) = 12.01 g/mol (carbon)
• M(H) = 1.01 g/mol (hydrogen)

Given the weight percentages:

• W(N) = 17.72%
• W(C) = 75.95%
• W(H) = 6.33%

Now, plug in the values and calculate W:

W = (17.72 * 14.01 + 75.95 * 12.01 + 6.33 * 1.01) / 100

W = (248.1472 + 911.3395 + 6.3933) / 100

W = 1165.88 / 100

W ≈ 11.66 g/mol

So, the molar mass of the compound is approximately 11.66 g/mol.