Вопрос задан 21.06.2023 в 12:25. Предмет Химия. Спрашивает Черкасова Валерия.

M(H2SO4)=20грамм. m(NaOH)=? m(NaSO4)=? m(H2O)=? 2NaOH+H2SO4=Na2SO4+2H2O

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Отвечает Смирнов Сергей.

Ответ:

Решение:

Хг 20г Хг Хг

2NaOH+H2SO4=Na2SO4+2H2O

80г 98г 142г 36г

m(NaOH)=20г×80г÷98г=16,32г

m(Na2SO4)=20г×142г÷98г=28,97г

m(H2O)=20г×36г÷98г=7,346г

Ответ:m(NaOH)=16,32г,m(Na2SO4)=28,97г,m(H2O)=7,346г

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

To find the masses of NaOH, Na2SO4, and H2O produced in the reaction between 2 moles of NaOH and 1 mole of H2SO4, we can use stoichiometry.

The balanced chemical equation for the reaction is:

2NaOH + H2SO4 → Na2SO4 + 2H2O

From the equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4 to produce 1 mole of Na2SO4 and 2 moles of H2O.

  1. Calculate the moles of H2SO4: Given mass of H2SO4 (M(H2SO4)) = 20 grams. The molar mass of H2SO4 is approximately 98 g/mol (21 + 32 + 416). Moles of H2SO4 = M(H2SO4) / Molar mass of H2SO4 Moles of H2SO4 = 20 g / 98 g/mol ≈ 0.2041 moles

  2. Use stoichiometry to find the moles of NaOH: From the balanced equation, 2 moles of NaOH react with 1 mole of H2SO4. Therefore, the moles of NaOH are also 0.2041 moles (since it's a 1:1 ratio).

  3. Calculate the moles of Na2SO4: From the balanced equation, 1 mole of H2SO4 produces 1 mole of Na2SO4. So, the moles of Na2SO4 are also 0.2041 moles.

  4. Calculate the moles of H2O: From the balanced equation, 1 mole of H2SO4 produces 2 moles of H2O. So, the moles of H2O are 2 times the moles of H2SO4. Moles of H2O = 2 * 0.2041 moles ≈ 0.4082 moles

  5. Calculate the masses of NaOH, Na2SO4, and H2O: To find the masses, you can use the molar masses of the compounds.

    • Molar mass of NaOH is approximately 40 g/mol (23 + 16 + 1).
    • Molar mass of Na2SO4 is approximately 142 g/mol (223 + 32 + 416).
    • Molar mass of H2O is approximately 18 g/mol (2*1 + 16).

Now, calculate the masses:

  • Mass of NaOH = Moles of NaOH * Molar mass of NaOH Mass of NaOH = 0.2041 moles * 40 g/mol ≈ 8.164 grams
  • Mass of Na2SO4 = Moles of Na2SO4 * Molar mass of Na2SO4 Mass of Na2SO4 = 0.2041 moles * 142 g/mol ≈ 28.952 grams
  • Mass of H2O = Moles of H2O * Molar mass of H2O Mass of H2O = 0.4082 moles * 18 g/mol ≈ 7.3536 grams

So, the masses of the substances are approximately as follows:

  • Mass of NaOH ≈ 8.164 grams
  • Mass of Na2SO4 ≈ 28.952 grams
  • Mass of H2O ≈ 7.3536 grams
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