Question

1. Для порції озону що містить 1,204*10^22 молекул, обчисліть: а) кількість речовини озону; б) об’єм цієї порції (н.у); в) кількість атомів оксигену 2. Для пропену C3H6 масою 90 г обчисліть: а) кількість речовини; б) об’єм газу (н.у); в) густину газу; г) густину пропену за гелієм Допоможіть, будь ласка! Не тільки відповідь, а й розв’язання :)

Answer 1

Ответ:

Объяснение:

смотри фото

Answer 2

Calculation for the Portion of Ozone

To calculate the quantity of ozone, volume, and the number of oxygen atoms in a portion of ozone containing 1.204 * 10^22 molecules, we can use the following formulas and constants:

1. The Avogadro constant (NA) is 6.022 * 10^23 mol^-1. 2. The molar mass of ozone (O3) is approximately 48 g/mol.

a) Quantity of Ozone (moles): The quantity of ozone can be calculated using the formula: Quantity of Ozone (moles) = Number of molecules / Avogadro constant

Substituting the given values: Quantity of Ozone (moles) = 1.204 * 10^22 / 6.022 * 10^23

b) Volume of the Portion (in standard conditions): The volume of the portion can be calculated using the ideal gas law: Volume (in standard conditions) = Quantity of Ozone (moles) * Molar volume (22.4 L/mol)

Substituting the calculated value from part a: Volume (in standard conditions) = Quantity of Ozone (moles) * 22.4 L/mol

c) Number of Oxygen Atoms: The number of oxygen atoms can be calculated by multiplying the quantity of ozone (moles) by 3 (since each ozone molecule contains 3 oxygen atoms).

Substituting the calculated value from part a: Number of Oxygen Atoms = Quantity of Ozone (moles) * 3

Calculation for Propene (C3H6)

To calculate the quantity of substance, volume of gas, gas density, and propene density with respect to helium for a 90 g sample of propene (C3H6), we can use the following formulas and constants:

1. The molar mass of propene (C3H6) is approximately 42 g/mol. 2. The molar volume of an ideal gas at standard conditions is 22.4 L/mol.

a) Quantity of Substance (moles): The quantity of substance can be calculated using the formula: Quantity of Substance (moles) = Mass of Substance / Molar Mass

Substituting the given values: Quantity of Substance (moles) = 90 g / 42 g/mol

b) Volume of Gas (in standard conditions): The volume of the gas can be calculated using the ideal gas law: Volume (in standard conditions) = Quantity of Substance (moles) * Molar Volume (22.4 L/mol)

Substituting the calculated value from part a: Volume (in standard conditions) = Quantity of Substance (moles) * 22.4 L/mol

c) Gas Density: The gas density can be calculated using the formula: Gas Density = Mass of Substance / Volume of Gas

Substituting the given values: Gas Density = 90 g / Volume of Gas

d) Propene Density with respect to Helium: The propene density with respect to helium can be calculated by dividing the gas density of propene by the gas density of helium.

Substituting the calculated value from part c and the known density of helium: Propene Density with respect to Helium = Gas Density / Helium Density

Please note that the density of helium is approximately 0.1785 g/L at standard conditions.

I hope this helps! Let me know if you have any further questions.