Question

А) (5a+3b)2 степень б) (3c-5)2 степень в) (x-3)2степень -x(x-6) Пожалуйста ребята

Answer 1

Calculation Explanation:

To solve the given expression, let's break it down step by step:

a) (5a + 3b)^2 To square a binomial, we need to multiply it by itself. In this case, we have (5a + 3b) as the binomial. So, squaring it would be: (5a + 3b)^2 = (5a + 3b) * (5a + 3b)

b) (3c - 5)^2 Similar to the previous step, we need to square the binomial (3c - 5): (3c - 5)^2 = (3c - 5) * (3c - 5)

c) (x - 3)^2 Again, we need to square the binomial (x - 3): (x - 3)^2 = (x - 3) * (x - 3)

d) -x(x - 6) This is a multiplication of two terms: -x and (x - 6).

Now, let's solve each part step by step.

Calculation Steps:

a) (5a + 3b)^2 To multiply two binomials, we can use the FOIL method (First, Outer, Inner, Last). Applying the FOIL method, we get: (5a + 3b)^2 = (5a * 5a) + (5a * 3b) + (3b * 5a) + (3b * 3b) Simplifying further, we have: (5a + 3b)^2 = 25a^2 + 15ab + 15ab + 9b^2 Combining like terms, we get: (5a + 3b)^2 = 25a^2 + 30ab + 9b^2

b) (3c - 5)^2 Using the FO