Question

Решение систем уравнений второй степени

Answer 1

Х^2-у^2=4200
4х+8у=5(х-у) 4х+8у=5х-5у 5х-4х=5у+8у х=13у
(13у)^2-у^2=4200
169у^2-у^2=4200
168у^2=4200
у^2=4200÷168
у^2=25
у1=5
у2= -5
х1=13×5=65
х2=13×(-5)= -65
65^2 - 25^2=4225-25=4200
(-65)^2-(-5)^2=4225-25=4200
ответ:х1 =65 х2= -65 у1=5 у2= -5