Question

Вычислить интеграл!!!!!!!

Answer 1

$\int {(5-3x)^7} \, dx =$
[ $u=5-3x; du=-3dx$ ] =
= $- \frac{1}{3} \int{u^7} \, du = -u^8/24 + C =$
= $- \frac{1}{24} (5-3x)^8 + C$