Question

Решите уравнение: -(x+2)^2+3=x-1

Answer 1

$-(x+2)^2+3=x-1 \\-(x^2+4x+4)=x-4 \\-x^2-4x-4=x-4 \\-x^2-4x=x \\x^2+5x=0 \\x(x+5)=0 \\x_1=0 \\x+5=0 \\x_2=-5$
Ответ: x1=0; x2=-5

Answer 2

X^2+2×2×x-2^2+3=x-1
X^2+4x-4+3=x-1
X^2+3x=0
X×(x+3)=0
X1=0 x+3=0
x2=-3