Question

√2(√8+4√2)

Answer 1

файл

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Answer 2

$\sqrt{2}(\sqrt{8}+4\sqrt{2})=\sqrt{2}(\sqrt{8}+\sqrt{16\cdot2})=\sqrt{2}(\sqrt{8}+\sqrt{32})= \sqrt{2}\cdot\sqrt{8}+\sqrt{2}\cdot\sqrt{32}=\sqrt{16}+\sqrt{64}=4+8=12$