Question

Сколько существует четырехзначных чисел таких , что первая цифра не делится на 2 , вторая - не делится на 3 , третья - не делится на 4 , а четвертая - не делится на 5? помогите плииз!!!!!!!!!!!!!!!!!!!!дам 5 баллов !!!!!!!!!!!1пожалууйста ! у меня 10 баллов дам 5!бог с ним дам все! пожалууйста!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!ПОМОГИТЕ!!!!!!!!!!!!!!умоляяяяяяяяяяяяяяяяяюююююююююююююююююююю

Answer 1

1111, 3231, 5556, 7863, 9537, 5738

Answer 2

Number of four-digit numbers that satisfy the given conditions

To find the number of four-digit numbers that satisfy the given conditions, we need to consider the restrictions on each digit.

1. The first digit should not be divisible by 2. 2. The second digit should not be divisible by 3. 3. The third digit should not be divisible by 4. 4. The fourth digit should not be divisible by 5.

Let's break down each condition and calculate the number of possibilities for each digit.

First digit restrictions (not divisible by 2)

The first digit cannot be 0, 2, 4, 6, or 8. This means there are 5 possibilities for the first digit.

Second digit restrictions (not divisible by 3)

The second digit cannot be 0, 3, 6, or 9. This means there are 7 possibilities for the second digit.

Third digit restrictions (not divisible by 4)

The third digit cannot be 0, 4, or 8. This means there are 7 possibilities for the third digit.

Fourth digit restrictions (not divisible by 5)

The fourth digit cannot be 0 or 5. This means there are 8 possibilities for the fourth digit.

To find the total number of four-digit numbers that satisfy all the conditions, we multiply the number of possibilities for each digit together:

Total number of possibilities = (number of possibilities for the first digit) * (number of possibilities for the second digit) * (number of possibilities for the third digit) * (number of possibilities for the fourth digit)

Total number of possibilities = 5 * 7 * 7 * 8 = 1960

Therefore, there are 1960 four-digit numbers that satisfy the given conditions.