Question

Система уравнения,пж 4х+у=-10 5х-2у=-19

Answer 1

$\left \{ {{4x+y=-10} \atop {5x-2y=-19}} \right. \\ \\ y=-10-4x \\ \\ 5x-2(-10-4x)=-19 \\ 5x+20+8x=-19 \\ 13x=-39 \\ x=-3 \\ \\ 4*(-3)+y=-10 \\ -12+y=-10 \\ y=2$