Question

Решите уравнение (3x+2)^2=10+3(x-2)(x+2)

Answer 1

9x^2+12x+4=10+3x^2-4
6x^2+12x-2=0
D=196
x1=-(2/3)
x2=-(4/3)

Answer 2

$(3x+2)^2=10+3(x-2)(x+2) \\ 9x^2+12x+4=10+3(x^2-4) \\ 9x^2+12x+4=10+3x^2-12 \\ 9x^2+12x+4=-2x+3x^2\\ 9x^2+12x+4+2x-3x^2=0\\ 6x^2+12x+6=0 \\ x^2+2x+1=0 \\ (x+1)^2=0 \\ x=-1$