Question

Решите пожалуйста! Срочно!

Answer 1

$(ab)^x=a^xb^x \\ \frac{a^x}{a^y} =a^{x-y} \\ a^x*a^y=a^{x+y}$



$\frac{15^{ \frac{2}{3} }*3^{ \frac{7}{3} }}{5^{-\frac{1}{3} }} =\frac{(5*3)^{ \frac{2}{3} }*3^{ \frac{7}{3} }}{5^{-\frac{1}{3} }}=\frac{5^{ \frac{2}{3} }*3^{ \frac{2}{3} }*3^{ \frac{7}{3} }}{5^{-\frac{1}{3} }}=5^{ \frac{2}{3} -(-\frac{1}{3} )}*3^{\frac{2}{3} +\frac{7}{3} }=5^{ \frac{3}{3} }*3^ \frac{9}{3} }= \\ =5^1*3^ 3=5*27=135$