Question

Преобразуйте в дробь выражения. *Премного благодарен буду тем кто это решит.)*а) а^2+3 _ 3-а б) x + x a^3 3a x-1 x+1в) x _ 4y^2 г) 2а+b - 4ab x-2y x^2-2xy 2a+b

Answer 1

$=\frac{3a^{2}+9-3a^{2}+3a^{3}}{3a^{3}}=\frac{a^{3}+9}{3a^{3}}$

$\frac{x^{2}+x+x^{2}-x}{x^{2}-1}=\frac{2x^{2}}{x^{2}-1}$ 

$=\frac{x^{2}-4y^{2}}{x(x-2y)}=\frac{(x-2y)(x+2y)}{x(x-2y)}=\frac{x+2y}{x}$

$=\frac{4a^{2}+b^{2}+4ab-4ab}{2a+b}=\frac{4a^{2}+b^{2}}{2a+b}$

 

 

Answer 2

А) (a^2+3):a^3-(3-a):3a
Б) x:(x-1)+x:(x+1)
В) x:(x-2y)-4y^2:(x^2-2xy)
G) 2ab-4ab:(2a+b)

Answer 3

To convert the given expressions into fractions, let's simplify each expression separately:

a) a^2 + 3 - 3a

To convert this expression into a fraction, we can combine the terms over a common denominator. The common denominator can be any number that both a^2 and 3a can divide evenly. In this case, we can use (a^2 + 3a) as the common denominator. So, we have:

(a^2 + 3 - 3a) / (a^2 + 3a)

b) x + x + a^3 + 3a + x - 1 + x + 1

Similarly, we can combine the like terms over a common denominator. The common denominator can be any number that both x and 3a can divide evenly. In this case, we can use (4x + 3a) as the common denominator. So, we have:

(x + x + a^3 + 3a + x - 1 + x + 1) / (4x + 3a)

c) x - 4y^2

Here, there is no need to convert it into a fraction as it is already in its simplest form.

d) 2a + b - 4ab + x - 2y + x^2 - 2xy + 2a + b

Again, we can combine the like terms over a common denominator. The common denominator can be any number that both 2a and 4ab can divide evenly. In this case, we can use (4a + 4ab) as the common denominator. So, we have:

(2a + b - 4ab + x - 2y + x^2 - 2xy + 2a + b) / (4a + 4ab)

By simplifying these expressions and combining like terms, we can convert them into fractions.