Question

у девочки были пятирублевые и двадцати рублевые монеты всего на сумму 300 р. сколько монет каждого вида было у девочки если десятирублевых монет было на 10 больше чем двадцатирублевых?

Answer 1

х-количество 20-рублевых монет

х+10-количество 5-рублевых

20х+5(х+10)=300

25х=250

х=10 - количество 20-рублевых монет

 

10+10=20 монет достоинством 5 рублей

Answer 2

Problem Analysis

To solve this problem, we need to find the number of five-ruble and twenty-ruble coins that the girl had, given that the total value of the coins is 300 rubles and the number of ten-ruble coins is 10 more than the number of twenty-ruble coins.

Solution

Let's assume that the number of twenty-ruble coins the girl had is x. Since the number of ten-ruble coins is 10 more than the number of twenty-ruble coins, the number of ten-ruble coins would be x + 10.

The total value of the coins is 300 rubles. We can express this as an equation:

5x + 20(x + 10) = 300

Simplifying the equation:

5x + 20x + 200 = 300

25x + 200 = 300

Subtracting 200 from both sides:

25x = 100

Dividing both sides by 25:

x = 4

So, the girl had 4 twenty-ruble coins. The number of ten-ruble coins would be 4 + 10 = 14.

Therefore, the girl had 4 twenty-ruble coins and 14 ten-ruble coins.

Answer

The girl had 4 twenty-ruble coins and 14 ten-ruble coins.

Please let me know if there is anything else I can help you with!