Question

1)a³b²c² из этого a=-1,b=-3,c=2 2)ab³c² из этого a=-2,b=-1C=-3 помогите пожалуйста

Answer 1

1)(-1)³(-3)²·2²=-1·9·4=-36 2)-2·(-1)³(-3)³=-2·(-1)·(-27)=-54

Answer 2

1) Let's solve the expression a³b²c² when a = -1, b = -3, and c = 2.

Substituting the given values, we have: a³b²c² = (-1)³(-3)²(2)²

Simplifying the expression, we get: (-1)³ = -1 (-3)² = 9 (2)² = 4

Therefore, a³b²c² = -1 * 9 * 4 = -36.

2) Now let's solve the expression ab³c² when a = -2, b = -1, and c = -3.

Substituting the given values, we have: ab³c² = (-2)(-1)³(-3)²

Simplifying the expression, we get: (-2) = -2 (-1)³ = -1 (-3)² = 9

Therefore, ab³c² = -2 * -1 * 9 = 18.

I hope this helps! Let me know if you have any further questions.