Question

Имеются 4 последовательных чётных числа.Если удвоенную сумму крайних чисел уменьшить на 2,то получится 34.Найти эти числа.Решить уравнением.заранее спасибо

Answer 1

2(2+х+х)-2=34
4+2х+2х-2=34
4х+2=34
4х=32
х=8

Answer 2

Даны числа x, x+2, x+4, x+6
x и x+6 - крайние числа
по условию 2(x+x+6)/2=34, отсюда 2х=28, х=14
Ответ: 14, 16, 18, 20

Answer 3

Problem Analysis

We are given that there are 4 consecutive even numbers. If we double the sum of the outermost numbers and subtract 2, we get 34. We need to find these numbers.

Solution

Let's assume the first even number is x. Since the numbers are consecutive even numbers, the second, third, and fourth even numbers will be x + 2, x + 4, and x + 6, respectively.

According to the given information, if we double the sum of the outermost numbers and subtract 2, we get 34. Mathematically, this can be represented as:

(2x + 2(x + 6)) - 2 = 34

Simplifying the equation:

2x + 2x + 12 - 2 = 34

4x + 10 = 34

Subtracting 10 from both sides:

4x = 24

Dividing both sides by 4:

x = 6

So, the first even number is 6. The second, third, and fourth even numbers are:

x + 2 = 6 + 2 = 8

x + 4 = 6 + 4 = 10

x + 6 = 6 + 6 = 12

Therefore, the four consecutive even numbers are 6, 8, 10, and 12.

Answer

The four consecutive even numbers are 6, 8, 10, and 12.