
Из одного города в другой выехали два мотоциклиста, расстояние между которыми 93 км. Скорость
второго мотоциклиста на 3 км/ч больше, чем скорость первого. Мотоциклисты встретились на расстоянии 45 км от первого города. Найдите скорость каждого мотоциклиста.

Ответы на вопрос




Problem Analysis
We are given that two motorcyclists start from one city and meet at a certain distance from the first city. The distance between them is 93 km, and the second motorcyclist's speed is 3 km/h faster than the first motorcyclist's speed. We need to find the speed of each motorcyclist.Solution
Let's assume the speed of the first motorcyclist is x km/h. Then the speed of the second motorcyclist will be x + 3 km/h.We know that the total distance between the two motorcyclists is 93 km. They meet at a distance of 45 km from the first city. This means that the first motorcyclist has traveled 45 km, and the second motorcyclist has traveled 93 - 45 = 48 km.
We can use the formula distance = speed × time to find the time taken by each motorcyclist.
For the first motorcyclist: 45 = x × t1, where t1 is the time taken by the first motorcyclist.
For the second motorcyclist: 48 = (x + 3) × t2, where t2 is the time taken by the second motorcyclist.
We can solve these two equations to find the values of x, t1, and t2.
Calculation
Let's solve the equations:From the first equation, we have: t1 = 45 / x
From the second equation, we have: t2 = 48 / (x + 3)
Since the total time taken by both motorcyclists is the same, we can equate t1 and t2:
45 / x = 48 / (x + 3)
Cross-multiplying, we get: 45(x + 3) = 48x
Expanding and simplifying, we get: 45x + 135 = 48x
Subtracting 45x from both sides, we get: 135 = 3x
Dividing both sides by 3, we get: x = 45
So, the speed of the first motorcyclist is 45 km/h, and the speed of the second motorcyclist is 45 + 3 = 48 km/h.
Answer
The speed of the first motorcyclist is 45 km/h, and the speed of the second motorcyclist is 48 km/h.

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