Question

Разложите на множители г) a(x-y)+bx-by= д) 3b-3c+a(b-c)= e) ab+2(b-d)-ad=

Answer 1

Г) a(x -y)+b(x -y) =(x -y)(a +b)

д) 3(b -c)+a(b -c)=(b-c)(3 +a)

e) a(b -d) +2(b-d)=(b-d)(a+2)

Answer 2

г) a(x-y) + bx - by = ax - ay + bx - by = (ax + bx) - (ay + by) = x(a + b) - y(a + b) = (a + b)(x - y)

д) 3b - 3c + a(b - c) = 3(b - c) + a(b - c) = (3 + a)(b - c)

е) ab + 2(b - d) - ad = ab + 2b - 2d - ad = (a - 1)(b - d) + b(a - d) = (a - 1)(b - d) + b(a - d) = (a - 1 + b)(b - d) = (a + b - 1)(b - d)