Question

В футбольной секции первоначально занималось в 3 раза больше учеников, чем в баскетбольной. Когда в футбольную секцию пришли ещё 9 учеников, а в в баскетбольную 33,то в секциях учеников стало поровну. Сколько учеников было в каждой секции? Решить с помощью уравнения. ПОЖАЛУЙСТА!!!

Answer 1

1) Пусть в баскетбольной было х учеников, тогда в футбольной 3х
х+33=3х+9
х-3х=9-33
-2х=-24
х=12 - было в баскетбольной секции
2) 12×3=36 - было в футбольной секции
Ответ: 12 и 36

Answer 2

Problem Analysis

We are given that initially, the football section had three times as many students as the basketball section. When 9 more students joined the football section and 33 students joined the basketball section, the number of students became equal in both sections. We need to find the number of students in each section.

Solution

Let's assume the number of students in the basketball section initially is x. Since the football section initially had three times as many students as the basketball section, the number of students in the football section initially is 3x.

After 9 more students joined the football section, the total number of students in the football section became 3x + 9. After 33 students joined the basketball section, the total number of students in the basketball section became x + 33.

According to the given information, the number of students became equal in both sections. Therefore, we can set up the following equation:

3x + 9 = x + 33

To solve this equation, we can simplify it as follows:

3x - x = 33 - 9

Simplifying further:

2x = 24

Dividing both sides by 2:

x = 12

So, initially, there were 12 students in the basketball section. Since the football section initially had three times as many students, there were 3 * 12 = 36 students in the football section.

Therefore, there were 12 students in the basketball section and 36 students in the football section.

Answer

There were 12 students in the basketball section and 36 students in the football section.