Question

помогите с заданием по тригонометрии 2sin 2п\3 - ctg п\6

Answer 1

$2 sin \frac{2 \pi }{3} -ctg \frac{ \pi }{6} =0$

Answer 2

Task: Trigonometry Expression

The given expression is: 2sin(2π/3) - ctg(π/6).

Solution:

To solve this expression, we can start by finding the values of sin(2π/3) and ctg(π/6) separately and then substitute them into the expression.

1. sin(2π/3): - Using the unit circle or a calculator, we find that sin(2π/3) equals √3/2. - Source:.

2. ctg(π/6): - The cotangent of an angle is the reciprocal of the tangent of the angle. So, ctg(π/6) is the same as 1/tan(π/6). - Using the formula for tangent, we have tan(π/6) = √3/3. - Therefore, ctg(π/6) = 1/(√3/3) = √3. - Source:.

Now, substituting these values back into the original expression: 2sin(2π/3) - ctg(π/6) = 2*(√3/2) - √3 = √3 - √3 = 0.

So, the value of the given expression 2sin(2π/3) - ctg(π/6) is 0.