Question

Катер за 2 ч проходит по течению реки на 5 км меньше чем за 3 ч против течения. Найдите скорость течения реки если собственная скорость. катера 25 км/ч.ПРОШУ ПОМОГИТЕ РЕШИТЬ !!!

Answer 1

Х-скорость течения,х+25-скорость по течению,25-х-скорость против течения
3(25-х)-2(25+х)=5
75-3х-50-2х=5
5х=25-5
5х=20
х=4км/ч-скорость течения

Answer 2

Problem Analysis

We are given that a boat travels 5 km less in 2 hours with the current than it does in 3 hours against the current. We need to find the speed of the current if the boat's own speed is 25 km/h.

Solution

Let's assume the speed of the current is x km/h.

When the boat is traveling with the current, its effective speed is the sum of its own speed and the speed of the current. Therefore, the boat's effective speed is 25 + x km/h.

According to the problem, the boat travels 5 km less in 2 hours with the current than it does in 3 hours against the current. This can be expressed as the following equation:

Distance traveled with the current = Distance traveled against the current - 5 km

Using the formula speed = distance / time, we can write the equation as:

(25 + x) * 2 = (25 - x) * 3 - 5

Now, let's solve this equation to find the value of x.

(25 + x) * 2 = (25 - x) * 3 - 5

Simplifying the equation:

50 + 2x = 75 - 3x - 5

Combining like terms:

2x + 3x = 75 - 5 - 50

5x = 20

Dividing both sides by 5:

x = 4

Therefore, the speed of the current is 4 km/h.

Answer

The speed of the current is 4 km/h.