Question

А) построите график функции y= -2X+4 Б)Проходит ли этот график через точку A(3;-2)? B)Проходит ли этот график через точку B(-12;26)? ПОМОГИТЕ!!!!!

Answer 1

Точка А-проходит
точка В-не проходит
подставь точки в уравнение
а)-2=-2
б)28=26(не верно)

Answer 2

Graph of the Function y = -2x + 4

The given function is in the form of \(y = kx + b\), where \(k = -2\) and \(b = 4\). This represents a linear function with a slope of -2 and a y-intercept of 4. The general form of the function is \(y = -2x + 4\).

Verification of Point A(3, -2)

To verify if the graph passes through the point A(3, -2), we can substitute x = 3 into the function and check if y = -2.

Substituting x = 3 into the function: \[y = -2(3) + 4\] \[y = -6 + 4\] \[y = -2\]

The calculated value of y is -2, which matches the y-coordinate of point A. Therefore, the graph passes through the point A(3, -2).

Verification of Point B(-12, 26)

To verify if the graph passes through the point B(-12, 26), we can substitute x = -12 into the function and check if y = 26.

Substituting x = -12 into the function: \[y = -2(-12) + 4\] \[y = 24 + 4\] \[y = 28\]

The calculated value of y is 28, which does not match the y-coordinate of point B. Therefore, the graph does not pass through the point B(-12, 26).

In summary: - The graph of the function \(y = -2x + 4\) passes through the point A(3, -2). - The graph of the function \(y = -2x + 4\) does not pass through the point B(-12, 26).

I hope this helps! If you have any further questions, feel free to ask.