Question

И так- вот только не надо писать всякую ерунду- это алгебра , а не русский ! мне просто действительно срочно надо эти решения и все- я баллы отдаю за решение,а не за письмо другу ! кто в силах помочь=помогите мне с этим: а) (2а+3)(2а-3) ; б) (у-5b)(y+5b) ; в) (0,8x+y)(y-0,8x) ; г) (b+0,5)в квадрате ; д) (а-2х)в квадрате ; е) (ab-1)в квадрате. спасибо

Answer 1

$(2a+3)(2a-3) =4a^2-6a+6a-9=4a^2-9\\ \\ (y-5b)(y+5b)=y^2+5by-5by-25b^2=y^2+25b^2\\ \\ (0,8x+y)(y-0,8x)=0,8xy-0,64x^2+y^2-0,8xy=-0,64x^2+y^2\\ \\ (b+0,5^2)=b^2+b+0,25\\ \\ (a-2x)^=a^2-4ax+4x^2\\ \\ (ab-1)^2=((ab)^2-2ab+1^2)=(ab)^2-2ab+1$

Answer 2

Solution for the Given Expressions

Here are the solutions for the given expressions:

a) (2a + 3)(2a - 3):

Expanding the given expression using the formula (a + b)(a - b) = a^2 - b^2, we get: (2a + 3)(2a - 3) = (2a)^2 - (3)^2 = 4a^2 - 9

So, the solution for (2a + 3)(2a - 3) is 4a^2 - 9.

b) (y - 5b)(y + 5b):

Using the formula (a - b)(a + b) = a^2 - b^2, we can expand the given expression: (y - 5b)(y + 5b) = y^2 - (5b)^2 = y^2 - 25b^2

Therefore, the solution for (y - 5b)(y + 5b) is y^2 - 25b^2.

c) (0.8x + y)(y - 0.8x):

Expanding the given expression using the formula (a + b)(a - b) = a^2 - b^2, we get: (0.8x + y)(y - 0.8x) = (0.8x)^2 - (y)^2 = 0.64x^2 - y^2

Hence, the solution for (0.8x + y)(y - 0.8x) is 0.64x^2 - y^2.

d) (b + 0.5)^2:

Expanding the given expression using the formula (a + b)^2 = a^2 + 2ab + b^2, we get: (b + 0.5)^2 = b^2 + 2(0.5)b + (0.5)^2 = b^2 + b + 0.25

So, the solution for (b + 0.5)^2 is b^2 + b + 0.25.

e) (a - 2x)^2:

Expanding the given expression using the formula (a - b)^2 = a^2 - 2ab + b^2, we get: (a - 2x)^2 = a^2 - 2(a)(2x) + (2x)^2 = a^2 - 4ax + 4x^2

Therefore, the solution for (a - 2x)^2 is a^2 - 4ax + 4x^2.

f) (ab - 1)^2:

Expanding the given expression using the formula (a - b)^2 = a^2 - 2ab + b^2, we get: (ab - 1)^2 = (ab)^2 - 2(ab)(1) + (1)^2 = a^2b^2 - 2ab + 1

Hence, the solution for (ab - 1)^2 is a^2b^2 - 2ab + 1.

I hope this helps! If you have any more questions or need further assistance, feel free to ask.