Question

Как найти 2 последовательных числа, произведение которых равно 156?

Answer 1

$a(a+1)=156 \\\ a^2+a-156=0 \\\ D=1+4\cdot156=625 \\\ a_1= \frac{-1-25}{2} =-13 \\\ a_2= \frac{-1+25}{2} =12 \\\ a_1+1=-13+1=-12 \\\ a_2+1=12+1=13$
Ответ: числа -13 и -12 и числа 12 и 13

Answer 2

Finding Two Consecutive Numbers with a Given Product

To find two consecutive numbers whose product is equal to 156, we can use algebraic equations to represent the numbers and solve for them.

Let's denote the first number as x and the second number as x + 1 (since they are consecutive).

The product of these two numbers can be represented as: x * (x + 1) = 156

We can solve this equation to find the values of x and x + 1.

Solution

Using the given equation x * (x + 1) = 156, we can solve for x:

x^2 + x - 156 = 0

Now, we can use the quadratic formula to solve for x: x = (-b ± √(b^2 - 4ac)) / (2a)

Where: - a = 1 - b = 1 - c = -156

Plugging these values into the quadratic formula, we get: x = (-1 ± √(1^2 - 4*1*(-156))) / (2*1) x = (-1 ± √(1 + 624)) / 2 x = (-1 ± √625) / 2 x = (-1 ± 25) / 2

So, the two possible values for x are: x = (-1 + 25) / 2 = 24 / 2 = 12 x = (-1 - 25) / 2 = -26 / 2 = -13

Therefore, the two consecutive numbers whose product is equal to 156 are 12 and 13.

This solution is based on the algebraic approach to solving the given problem.