Question

3x-6=0 1/3x=2 x=2x-2 6=x-3 x-1=x x(x+2)=0 0,8(9+2x)=0,5(2-3)

Answer 1

1) 3х=6      х=2

2) х= 2: 1/3   х= 2х3=6

3) х=2х-2    х-2х=-2   - х=-2   х=2

6=х-3   х=6+3=9

5)  х-1=х     нет корней

6) х(х+2)=0   х=0 или х+2=0     х=0 или х=-2

7) 0,8 (9+2х)=0,5 (2-3)   здесь ничего не пропущено?

 

 

Answer 2

It looks like you've provided a series of equations and expressions, and I believe you're asking for a detailed solution to each of them. I'll start by breaking down each equation and expression, and then provide a step-by-step solution for each one.

Equation 1: 3x - 6 = 0

To solve for x, we can start by isolating the variable x. Add 6 to both sides of the equation: 3x - 6 + 6 = 0 + 6 3x = 6 Now, divide both sides by 3 to solve for x: 3x / 3 = 6 / 3 x = 2

Equation 2: 1/3x = 2

To solve for x, we can start by isolating the variable x. Multiply both sides by 3 to get rid of the fraction: 3 * (1/3x) = 3 * 2 1x = 6 x = 6

Equation 3: x = 2x - 2

To solve for x, we can start by isolating the variable x. Subtract 2x from both sides of the equation: x - 2x = -2 -1x = -2 Now, multiply both sides by -1 to solve for x: (-1) * (-1x) = (-1) * (-2) x = 2

Equation 4: 6 = x - 3

To solve for x, we can start by isolating the variable x. Add 3 to both sides of the equation: 6 + 3 = x - 3 + 3 9 = x

Equation 5: x - 1 = x

This equation indicates that x - 1 is equal to x. This is not possible, as subtracting 1 from x should result in a smaller value. Therefore, this equation does not have a valid solution.

Equation 6: x(x + 2) = 0

This equation indicates that either x = 0 or (x + 2) = 0. For x(x + 2) = 0, the solutions are: x = 0 or x + 2 = 0 So, x = 0 or x = -2

Equation 7: 0.8(9 + 2x) = 0.5(2 - 3)

To solve for x, we can start by simplifying the equation. First, simplify the right-hand side: 0.8(9 + 2x) = 0.5(-1) Now, simplify each side of the equation: 7.2 + 1.6x = -0.5 Subtract 7.2 from both sides: 1.6x = -7.7 Divide by 1.6 to solve for x: x ≈ -4.8125

I hope this provides the detailed answers you were looking for. If you have any more equations or need further assistance, feel free to ask!