Question

30 БАЛЛОВ СРОЧНООО!!! Упростить выражение 2/x-4 -x+8/x^2-16 -1/x с объяснениями пожалуйста!

Answer 1

$\frac{2}{(x-4} -\frac{x+8}{(x-4)(x+4)} - \frac{1}{x}$
первую дробь умножаем на x(x-4)
вторую на x 
третью на (x-4)(x+4)
$\frac{2x^2+8x-x^2-8x-x^2+16}{x(x-4)(x+4)}$
$\frac{16}{x(x-4)(x+4)}$

Answer 2

Simplifying the Expression 2/x-4 - x+8/x^2-16 - 1/x

To simplify the given expression, we'll start by finding a common denominator for the fractions and then combine like terms.

The given expression is: 2/x-4 - x+8/x^2-16 - 1/x

First, let's find the common denominator for the fractions. The common denominator for the given expression is x(x+4)(x-4).

Now, we'll rewrite each fraction with the common denominator and then combine like terms.

The expression becomes: 2(x+4)(x-4)/x(x+4)(x-4) - (x^2-8)/x(x+4)(x-4) - (x(x+4)(x-4))/x(x+4)(x-4)

Now, we'll combine the numerators over the common denominator: (2(x+4)(x-4) - (x^2-8) - x(x+4)(x-4))/x(x+4)(x-4)

Simplify the numerator: (2x^2 - 8x + 8 - x^2 + 8 - x^3 - 4x^2 + 16x)/x(x+4)(x-4)

Combine like terms in the numerator: (-x^3 - 2x^2 + 16x + 8)/x(x+4)(x-4)

So, the simplified expression is: (-x^3 - 2x^2 + 16x + 8)/x(x+4)(x-4)

This is the simplified form of the given expression.