Question

8x^2=11x+10 помогите пажалуста

Answer 1

8x²=11x+10;
8х²-11x-10=0;
D=b²-4ac;
D=(-11)²-4*8*(-10)=121+320=441;
√D=21;
х1=(-b-√D)/2a=(11-21)/2*8=-10/16=-5\8;
x2=(-b+√D)/2a=(11+21)/2*8=32/16=2.
Ответ:  (-5/8;2)

Answer 2

Наверное так ........

Answer 3

Solving the Equation 8x^2 = 11x + 10

To solve the equation 8x^2 = 11x + 10, we can use the quadratic formula or factorization. Let's solve it using the quadratic formula.

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

Here, a = 8, b = -11, and c = -10. Plugging these values into the quadratic formula gives us:

x = (-(-11) ± √((-11)^2 - 4*8*(-10))) / (2*8)

x = (11 ± √(121 + 320)) / 16

x = (11 ± √441) / 16

x = (11 ± 21) / 16

So, the solutions for x are:

x = (11 + 21) / 16 = 32 / 16 = 2

x = (11 - 21) / 16 = -10 / 16 = -5/8

Therefore, the solutions for the equation 8x^2 = 11x + 10 are x = 2 and x = -5/8.

I hope this helps! If you have any further questions, feel free to ask.