Question

Найдите координаты вершины параболы у=-(х+1)^2-4. постройте график функции

Answer 1

Y=-(x+1)ˇ2-4
V(-1,-4)

y=(x+a)ˇ2 +b
V(-a,b)

Answer 2

Finding the Coordinates of the Vertex of the Parabola and Graphing the Function

The given parabola is in the form: y = -(x + 1)^2 - 4.

To find the coordinates of the vertex of the parabola, we can use the standard form of a parabola equation: y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.

Coordinates of the Vertex:

The vertex of the parabola is at the point (-1, -4).

Graph of the Function:

Now, let's plot the graph of the function y = -(x + 1)^2 - 4.

The graph will be plotted with the vertex at (-1, -4) and the parabola opening downwards.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.