Question

В три коробки надо разложить 55 мячей так, чтобы в первой было мячей в 3 раза больше, чем во второй,а в третьей - на 5 мячей больше, чем во второй. Сколько мячей будет в каждой коробке?

Answer 1

Всего 55
1 коробка - 3x
2 коробка - х
3 коробка - х+5
Решение
3х+х+х+5=55
5х=55-5
5х=50
Х=10(вторая коробка)
3*10=30(первая коробка)
10+5 =15 (третья коробка)

Answer 2

Solving the Problem of Distributing 55 Balls into Three Boxes

To solve this problem, we need to distribute 55 balls into three boxes in such a way that the first box contains three times as many balls as the second box, and the third box contains 5 more balls than the second box. Let's calculate the number of balls in each box.

Calculating the Number of Balls in Each Box

Let's denote: - The number of balls in the second box as x. - The number of balls in the first box as 3x (three times as many as the second box). - The number of balls in the third box as x + 5 (five more than the second box).

We can set up the following equation to represent the total number of balls: x + 3x + (x + 5) = 55

Solving for x: 5x + 5 = 55 5x = 50 x = 10

So, the number of balls in each box is: - First box: 3x = 3 * 10 = 30 balls - Second box: x = 10 balls - Third box: x + 5 = 10 + 5 = 15 balls

Therefore, the distribution of 55 balls into the three boxes is as follows: - First box: 30 balls - Second box: 10 balls - Third box: 15 balls

This distribution satisfies the given conditions.