
Из четырех жертвователей второй дал вдвое больше первого третий втрое больше второго четвертый
вчетверо больше третьего а все вместе дали 132рупий сколько дал каждый

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Problem Analysis
We are given that there are four donors, and each subsequent donor gives a certain amount more than the previous donor. The total amount donated by all four donors is 132 rupees. We need to determine how much each donor gave.Solution
Let's assign variables to represent the amounts donated by each donor. We'll call the first donor's donation "x" rupees.According to the given information: - The second donor gave twice as much as the first donor. - The third donor gave three times as much as the second donor. - The fourth donor gave four times as much as the third donor.
Based on this information, we can set up the following equations:
1. The second donor's donation: 2x rupees. 2. The third donor's donation: 3 * (2x) = 6x rupees. 3. The fourth donor's donation: 4 * (6x) = 24x rupees.
The total amount donated by all four donors is 132 rupees. Therefore, we can write the equation:
x + 2x + 6x + 24x = 132
Simplifying the equation:
33x = 132
Dividing both sides of the equation by 33:
x = 4
Now that we know the value of x, we can calculate the donations of each donor:
- The first donor gave 4 rupees. - The second donor gave 2 * 4 = 8 rupees. - The third donor gave 6 * 4 = 24 rupees. - The fourth donor gave 24 * 4 = 96 rupees.
Therefore, each donor gave the following amounts: - The first donor gave 4 rupees. - The second donor gave 8 rupees. - The third donor gave 24 rupees. - The fourth donor gave 96 rupees.
Answer
Each donor gave the following amounts: - The first donor gave 4 rupees. - The second donor gave 8 rupees. - The third donor gave 24 rupees. - The fourth donor gave 96 rupees.

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